How to calculate the next number in the sequence 8, 64, 80, 136, 152 with Pascal

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(*
 
Pattern Explanation:
 
The sequence is: 8, 64, 80, 136, 152
 
Compute the differences between consecutive numbers:
64  - 8   = 56
80  - 64  = 16
136 - 80  = 56
152 - 136 = 16
 
The pattern clearly alternates:
+56, +16, +56, +16, ...
 
8 + 56   =  64
64 + 16  =  80
80 + 56  = 136
136 + 16 = 152
 
Since the last step was +16, the next step must be +56.
Therefore, the next number is: 152 + 56 = 208
 
*)

program NextSequenceNumber;

uses
  SysUtils;

// ------------------------------------------------------------
// Function to compute the next number in the alternating-difference pattern
// ------------------------------------------------------------
function NextNumberInSequence(const seq: array of Integer; size: Integer): Integer;
var
  diff: array[0..100] of Integer;  // large enough for this example
  diffCount: Integer;
  i: Integer;
  nextDiff: Integer;
begin
  // Compute differences between consecutive numbers
  diffCount := 0;
  for i := 1 to size - 1 do
  begin
    diff[diffCount] := seq[i] - seq[i - 1];
    Inc(diffCount);
  end;

  // The pattern alternates: 56, 16, 56, 16, ...
  // To continue the pattern, take the second-to-last difference (56)
  nextDiff := diff[diffCount - 2];

  // Return the next number in the sequence
  NextNumberInSequence := seq[size - 1] + nextDiff;
end;

var
  seq: array[0..4] of Integer = (8, 64, 80, 136, 152);
  nextValue: Integer;

begin
  // Compute the next number using the function
  nextValue := NextNumberInSequence(seq, Length(seq));

  WriteLn('Next number in the sequence: ', nextValue);
end.



(*
run:

Next number in the sequence: 208

*)

 



answered May 11 by avibootz

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