How to calculate the next number in the sequence 8, 64, 80, 136, 152 with Java

1 Answer

0 votes
/**
 
Pattern Explanation:
 
The sequence is: 8, 64, 80, 136, 152
 
Compute the differences between consecutive numbers:
64  - 8   = 56
80  - 64  = 16
136 - 80  = 56
152 - 136 = 16
 
The pattern clearly alternates:
+56, +16, +56, +16, ...
 
8 + 56   =  64
64 + 16  =  80
80 + 56  = 136
136 + 16 = 152
 
Since the last step was +16, the next step must be +56.
Therefore, the next number is: 152 + 56 = 208
 
*/

public class NextSequenceNumber {

    // ------------------------------------------------------------
    // Function to compute the next number in the alternating-difference pattern
    // ------------------------------------------------------------
    public static int nextNumberInSequence(int[] seq) {
        // Compute differences between consecutive numbers
        int[] diff = new int[100];  // large enough for this example
        int diffCount = 0;

        for (int i = 1; i < seq.length; i++) {
            diff[diffCount++] = seq[i] - seq[i - 1];
        }

        // The pattern alternates: 56, 16, 56, 16, ...
        // To continue the pattern, take the second-to-last difference (56)
        int nextDiff = diff[diffCount - 2];

        // Return the next number in the sequence
        return seq[seq.length - 1] + nextDiff;
    }

    public static void main(String[] args) {
        // The given sequence
        int[] seq = {8, 64, 80, 136, 152};

        // Compute the next number using the function
        int nextValue = nextNumberInSequence(seq);

        System.out.println("Next number in the sequence: " + nextValue);
    }
}



/*
run:

Next number in the sequence: 208

*/

 



answered May 11 by avibootz

Related questions

...