How to calculate the 100th term of the sequence 8, 64, 80, 136, 152 in Pascal

1 Answer

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(*
 
Pattern Explanation:
 
The sequence is: 8, 64, 80, 136, 152
 
Compute the differences between consecutive numbers:
64  - 8   = 56
80  - 64  = 16
136 - 80  = 56
152 - 136 = 16
 
The pattern clearly alternates:
+56, +16, +56, +16, ...
 
8   + 56 =  64
64  + 16 =  80
80  + 56 = 136
136 + 16 = 152
 
This alternating pattern continues forever.
 
Even-term formula:
Term(2) = 64
Each pair adds: 56 + 16 = 72
 
Number of even terms up to Term(100):
100 / 2 = 50 even terms
 
Number of full pairs after Term(2):
50 - 1 = 49 pairs
 
Formula for even terms:
Term(n) = 64 + 72 × (n/2 - 1)
 
For n = 100:
Term(100) = 64 + 72 × 49 = 3592
 
*)

program NextSequenceNumber;

{$mode objfpc}

uses
  SysUtils;

// ------------------------------------------------------------
// Function to compute the nth term using the even-term formula
// ------------------------------------------------------------
function NthTerm(n: Integer): Integer;
var
  evenTerm: Integer;
begin
  if n = 1 then
  begin
    Result := 8;  // first term is fixed
    Exit;
  end;

  if (n mod 2 = 0) then
  begin
    // Even term formula
    Result := 64 + 72 * (n div 2 - 1);
  end
  else
  begin
    // Odd term = previous even term + 16
    evenTerm := 64 + 72 * ((n - 1) div 2 - 1);
    Result := evenTerm + 16;
  end;
end;

var
  n: Integer;
  resultValue: Integer;

begin
  n := 100;

  resultValue := NthTerm(n);

  WriteLn('The 100th term of the sequence is: ', resultValue);
end.



(*
Run:
 
The 100th term of the sequence is: 3592
 
*)

 



answered 16 hours ago by avibootz

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