How to calculate the next number in the sequence 8, 64, 80, 136, 152 with C++

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/*

Pattern Explanation:

The sequence is: 8, 64, 80, 136, 152

Compute the differences between consecutive numbers:
64  - 8   = 56
80  - 64  = 16
136 - 80  = 56
152 - 136 = 16

The pattern clearly alternates:
+56, +16, +56, +16, ...

8 + 56   =  64
64 + 16  =  80
80 + 56  = 136
136 + 16 = 152

Since the last step was +16, the next step must be +56.
Therefore, the next number is: 152 + 56 = 208

*/

#include <iostream>
#include <vector>

// ------------------------------------------------------------
// Function to compute the next number in the alternating-difference pattern
// ------------------------------------------------------------
int nextNumberInSequence(const std::vector<int>& seq) {
    // Compute differences between consecutive numbers
    std::vector<int> diff;
    
    for (size_t i = 1; i < seq.size(); i++) {
        diff.push_back(seq[i] - seq[i - 1]);
    }

    // The pattern alternates: 56, 16, 56, 16, ...
    // To continue the pattern, take the second-to-last difference (56)
    int nextDiff = diff[diff.size() - 2];

    // Return the next number in the sequence
    return seq.back() + nextDiff;
}

int main() {
    // The given sequence
    std::vector<int> seq = {8, 64, 80, 136, 152};

    // Compute the next number using the function
    int nextValue = nextNumberInSequence(seq);

    std::cout << "Next number in the sequence: " << nextValue << std::endl;
}


/*
run:

Next number in the sequence: 208

*/

 



answered 1 day ago by avibootz

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