Question

How to convet decimal number base-12 number in TypeScript

Answer 1

// Converts a decimal number to base-12 and returns it as a string
function decimalToBase12(decimalNumber: number): string {
    if (decimalNumber === 0) {
        return "0";
    }

    const digits: string = "0123456789AB"; // Base-12 digits (A = 10, B = 11)
    const base12: string[] = [];

    while (decimalNumber > 0) {
        const remainder: number = decimalNumber % 12;
        base12.push(digits[remainder]);
        decimalNumber = Math.floor(decimalNumber / 12);
    }

    // Reverse to get the correct order
    return base12.reverse().join('');
}

let decimalNumber: number = 100;
let base12Number: string = decimalToBase12(decimalNumber);
console.log(`Base-12 representation: ${base12Number}`);

decimalNumber = 19621;
base12Number = decimalToBase12(decimalNumber);
console.log(`Base-12 representation: ${base12Number}`);



/*
run:

"Base-12 representation: 84" 
"Base-12 representation: B431" 

*/

 

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