How to convet decimal number base-12 number in Kotlin

1 Answer

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fun decimalToBase12(decimalNumber: Int): String {
    // Converts a decimal number to base-12 and returns it as a string.
    if (decimalNumber == 0) return "0"

    val digits = "0123456789AB" // Base-12 digits (A = 10, B = 11)
    val base12 = mutableListOf<Char>()
    var num = decimalNumber

    while (num > 0) {
        val remainder = num % 12
        base12.add(digits[remainder])
        num /= 12
    }

    // Reverse to get the correct order
    return base12.reversed().joinToString("")
}

fun main() {
    val decimalNumber1 = 100
    val base12Number1 = decimalToBase12(decimalNumber1)
    println("Base-12 representation: $base12Number1")

    val decimalNumber2 = 19621
    val base12Number2 = decimalToBase12(decimalNumber2)
    println("Base-12 representation: $base12Number2")
}


/*
run:

Base-12 representation: 84
Base-12 representation: B431

*/

 



answered Sep 11, 2025 by avibootz

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