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How to convet decimal number base-12 number in Scala

1 Answer

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object DecimalToBase12 {

  // Converts a decimal number to base-12 and returns it as a string
  def decimalToBase12(decimalNumber: Int): String = {
    if (decimalNumber == 0) return "0"

    val digits = "0123456789AB" // Base-12 digits (A = 10, B = 11)
    var num = decimalNumber
    val base12 = scala.collection.mutable.ListBuffer[Char]()

    while (num > 0) {
      val remainder = num % 12
      base12 += digits.charAt(remainder)
      num /= 12
    }

    // Reverse to get the correct order
    base12.reverse.mkString
  }

  def main(args: Array[String]): Unit = {
    val decimalNumber1 = 100
    val base12Number1 = decimalToBase12(decimalNumber1)
    println(s"Base-12 representation: $base12Number1")

    val decimalNumber2 = 19621
    val base12Number2 = decimalToBase12(decimalNumber2)
    println(s"Base-12 representation: $base12Number2")
  }
}


/*
run:

Base-12 representation: 84
Base-12 representation: B431

*/

 



answered Sep 11, 2025 by avibootz

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