How to get the lower 8 bits of an int in C++

1 Answer

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#include <iostream>

void print_bits(int n, int size) {
    for (int i = 1 << (size - 1); i > 0; i = i / 2) {
        (n & i) ? std::cout << "1" : std::cout << "0";
    }
}
  
int main(void)
{
    int n = 1957;
     
    print_bits(n, 16);
    std::cout << "\n";
     
    unsigned low8bits = n & 0xFF;
  
    print_bits(low8bits, 16);
}
  
  
  
  
/*
run:
 
0000011110100101
0000000010100101
  
*/

 



answered Apr 2, 2024 by avibootz

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