How to get the lower 8 bits of an int in C

1 Answer

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#include <stdio.h>
 
void print_bits(int n, int size) {
    for (int i = 1 << (size - 1); i > 0; i = i / 2) {
        (n & i) ? printf("1") : printf("0");
    }
}
 
int main(void)
{
    int n = 1957;
    
    print_bits(n, 16);
    printf("\n");
    
    unsigned low8bits = n & 0xFF;
 
    print_bits(low8bits, 16);
    
    return 0;
}
 
 
 
 
/*
run:

0000011110100101
0000000010100101
 
*/

 



answered Apr 2, 2024 by avibootz

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