Question

How to get the lower 8 bits of an int in Go

Answer 1

package main

import (
    "fmt"
    "strconv"
)

func printBinary(n int, width int) string {
    b := strconv.FormatInt(int64(n), 2)
    for len(b) < width {
        b = "0" + b
    }
    
    return b
}

func main() {
    n := 1957

    // Print 16-bit binary representation of n
    fmt.Println(printBinary(n, 16))

    // Get the low 8 bits
    low8bits := n & 0xFF
    fmt.Println(printBinary(low8bits, 16)) // Also padded to 16 bits
}



/*
run:

0000011110100101
0000000010100101

*/

 

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