How to rearrange array and set even indexed values to be smaller than odd indexed values in Node.js

1 Answer

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function RearrangeOddEven(arr) {
    for (let i = 0; i < arr.length - 1; i++) {
        if (i % 2 == 0 && arr[i] > arr[i + 1]) {
            [arr[i], arr[i + 1]] = [arr[i + 1], arr[i]];
        }
        if (i % 2 != 0 && arr[i] < arr[i + 1]) {
            [arr[i], arr[i + 1]] = [arr[i + 1], arr[i]];
        }
    }
}
    
const arr = [1, 2, 4, 5, 8, 6, 7, 3];

RearrangeOddEven(arr);

console.log(arr);



/*
run:

[1, 4, 2, 8, 5, 7, 3, 6]


*/

 



answered Nov 14, 2022 by avibootz
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