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How to rearrange array and set even indexed values to be smaller than odd indexed values in TypeScript

1 Answer

0 votes
function RearrangeOddEven(arr : number[]) {
    for (let i :number = 0; i < arr.length - 1; i++) {
        if (i % 2 == 0 && arr[i] > arr[i + 1]) {
            [arr[i], arr[i + 1]] = [arr[i + 1], arr[i]];
        }
        if (i % 2 != 0 && arr[i] < arr[i + 1]) {
            [arr[i], arr[i + 1]] = [arr[i + 1], arr[i]];
        }
    }
}
     
const arr : number[] = [1, 2, 3, 5, 8, 6, 7, 4];
 
RearrangeOddEven(arr);
 
console.log(arr);
 
 
 
 
/*
run:
 
[1, 3, 2, 8, 5, 7, 4, 6]
 
*/

 



answered Nov 14, 2022 by avibootz
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