Question

How to rearrange array and set even indexed values to be smaller than odd indexed values in JavaScript

Answer 1

function RearrangeOddEven(arr) {
    for (let i = 0; i < arr.length - 1; i++) {
        if (i % 2 == 0 && arr[i] > arr[i + 1]) {
            [arr[i], arr[i + 1]] = [arr[i + 1], arr[i]];
        }
        if (i % 2 != 0 && arr[i] < arr[i + 1]) {
            [arr[i], arr[i + 1]] = [arr[i + 1], arr[i]];
        }
    }
}
    
const arr = [1, 2, 3, 5, 8, 6, 7, 4];

RearrangeOddEven(arr);

console.log(arr);




/*
run:

[1, 3, 2, 8, 5, 7, 4, 6]

*/

 

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