Question

How to return an array of integers from existing string in TypeScript

Answer 1

function stringAllIntegers(str : string) : any {
    return str.match(/^\d+|\d+\b|\d+(?=\w)/g);
}
  

console.log(stringAllIntegers('typescript2022 2023 2024 2025')); 
console.log(stringAllIntegers('F 35 22 15')); 
console.log(stringAllIntegers('6 a 2 b 100 c')); 




/*
run:

["2022", "2023", "2024", "2025"] 
["35", "22", "15"] 
["6", "2", "100"] 

*/

 

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Answer 2

function stringAllIntegers(str : string) : any {
    return str.match(/^\d+|\d+\b|\d+(?=\w)/g).map(function (v) {return +v;})
}
  

console.log(stringAllIntegers('typescript2022 2023 2024 2025')); 
console.log(stringAllIntegers('F 35 22 15')); 
console.log(stringAllIntegers('6 a 2 b 100 c')); 




/*
run:

[2022, 2023, 2024, 2025] 
[35, 22, 15] 
[6, 2, 100] 

*/

 

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