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How to return an array of integers from existing string in Node.js

2 Answers

0 votes
function stringAllIntegers(str) {
    return str.match(/^\d+|\d+\b|\d+(?=\w)/g);
}
 
console.log(stringAllIntegers('nodejs2022 2023 2024 2025 2026')); 
console.log(stringAllIntegers('F 35 22 15')); 
console.log(stringAllIntegers('7 a 9 b 30 c')); 
 
 
 
 
/*
run:
 
[ '2022', '2023', '2024', '2025', '2026' ]
[ '35', '22', '15' ]
[ '7', '9', '30' ]
 
*/

 



answered Jun 5, 2022 by avibootz
0 votes
function stringAllIntegers(str) {
    return str.match(/^\d+|\d+\b|\d+(?=\w)/g).map(function (v) {return +v;})
}
 
console.log(stringAllIntegers('nodejs2022 2023 2024 2025 2026')); 
console.log(stringAllIntegers('F 35 22 15')); 
console.log(stringAllIntegers('7 a 9 b 30 c')); 
 
 
 
 
/*
run:
 
[ 2022, 2023, 2024, 2025, 2026 ]
[ 35, 22, 15 ]
[ 7, 9, 30 ]
 
*/

 



answered Jun 5, 2022 by avibootz
...