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How to return an array of integers from existing string in JavaScript

2 Answers

0 votes
function stringAllIntegers(str) {
    return str.match(/^\d+|\d+\b|\d+(?=\w)/g);
}
 
console.log(stringAllIntegers('javascript2022 2023 2024')); 
console.log(stringAllIntegers('F 35 22 15')); 
console.log(stringAllIntegers('3 a 1 b 89 c')); 
 
 
 
 
/*
run:
 
["2022", "2023", "2024"]
["35", "22", "15"]
["3", "1", "89"]
 
*/

 



answered Jun 5, 2022 by avibootz
0 votes
function stringAllIntegers(str) {
    return str.match(/^\d+|\d+\b|\d+(?=\w)/g).map(function (v) {return +v;})
}
 
console.log(stringAllIntegers('javascript2022 2023 2024')); 
console.log(stringAllIntegers('F 35 22 15')); 
console.log(stringAllIntegers('3 a 1 b 89 c')); 
 
 
 
 
/*
run:
 
[2022, 2023, 2024]
[35, 22, 15]
[3, 1, 89]
 
*/

 



answered Jun 5, 2022 by avibootz
...