Question

How to check if array contains all elements of a given range in TypeScript

Answer 1

function check_elements(arr: number[], rang_from: number, rang_to: number) {
	const range = rang_to - rang_from;
  	const size = arr.length;
          
  	for (let i = 0; i < size; i++) {
         if (arr[i] >= rang_from && arr[i] <= rang_to) {
              const j = arr[i] - rang_from;
              if (arr[j] > 0) {
                  arr[j] *= -1;
              }
              let s = "";
              for (let k = 0; k < size; k++) {
                   s += arr[k] + " ";
              }
              console.log(s);
            }
        }
       
        for (let i = 0; i < range; i++) {
            if (arr[i] > 0)
                return false;
        }
        
        return true;
}

const arr = [1, 4, 5, 2, 3, 7, 8, 3, 9, 4, 4, 0, 6];
const rang_from = 3, rang_to = 7; 
 
if (check_elements(arr, rang_from, rang_to))
    console.log("Yes");
else
    console.log("No");
 
 
 
 
   
/*
run:
         
"1 -4 5 2 3 7 8 3 9 4 4 0 6 " 
"1 -4 -5 2 3 7 8 3 9 4 4 0 6 " 
"-1 -4 -5 2 3 7 8 3 9 4 4 0 6 " 
"-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 " 
"-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 " 
"-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 " 
"-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 " 
"-1 -4 -5 -2 -3 7 8 3 9 4 4 0 6 " 
"Yes" 
 
*/

 

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