Question

How to check if array contains all elements of a given range in PHP

Answer 1

function check_elements($arr, $rang_from, $rang_to) {
    $range = $rang_to - $rang_from;
    $size = count($arr);
        
    for ($i = 0; $i < $size; $i++) {
        if ($arr[$i] >= $rang_from && $arr[$i] <= $rang_to) {
            $j = $arr[$i] - $rang_from;
            if ($arr[$j] > 0) {
                $arr[$j] *= -1;
            }
            for ($k = 0; $k < $size; $k++) {
                echo $arr[$k] . " ";
            }
            echo "\n";
        }
    }
     
    for ($i = 0; $i < $range; $i++) {
        if ($arr[$i] > 0)
            return false;
        }
        return true;
    }
    
$arr= array(1, 4, 5, 2, 3, 7, 8, 3, 9, 4, 4, 0, 6);
$rang_from = 3;
$rang_to = 7; 

if (check_elements($arr, $rang_from, $rang_to))
    echo "Yes";
else
    echo "No";


 
 
  
/*
run:
        
1 -4 5 2 3 7 8 3 9 4 4 0 6 
1 -4 -5 2 3 7 8 3 9 4 4 0 6 
-1 -4 -5 2 3 7 8 3 9 4 4 0 6 
-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 
-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 
-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 
-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 
-1 -4 -5 -2 -3 7 8 3 9 4 4 0 6 
Yes

*/

 

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