Question

How to check if array contains all elements of a given range in C

Answer 1

#include <stdio.h>
#include <stdbool.h>
 
bool check_elements(int arr[], int size, int rang_from, int rang_to) {
    int range = rang_to - rang_from;
    for (int i = 0; i < size; i++) {
        if (arr[i] >= rang_from && arr[i] <= rang_to) {
            int j = arr[i] - rang_from;
            if (arr[j] > 0) {
                arr[j] *= -1;
            }
            for (int i = 0; i < size; i++) {
                printf("%d ", arr[i]);
            }
            printf("\n");
        }
    }
 
    for (int i = 0; i < range; i++) {
        if (arr[i] > 0)
            return false;
    }
    return true;
}
   
int main()
{
    int arr[] = {1, 4, 5, 2, 3, 7, 8, 3, 9, 4, 4, 0, 6};
    int size = sizeof(arr) / sizeof(arr[0]);
    int rang_from = 3, rang_to = 7; 
   
    if (check_elements(arr, size, rang_from, rang_to))
        puts("Yes");
    else
        puts("No");
 
    return 0;
}
 
 
 
  
/*
run:
        
1 -4 5 2 3 7 8 3 9 4 4 0 6 
1 -4 -5 2 3 7 8 3 9 4 4 0 6 
-1 -4 -5 2 3 7 8 3 9 4 4 0 6 
-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 
-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 
-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 
-1 -4 -5 2 -3 7 8 3 9 4 4 0 6 
-1 -4 -5 -2 -3 7 8 3 9 4 4 0 6 
Yes
   
*/

 

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