Question

How to calculate generic root of a number in Java

Answer 1

public class MyClass {
    public static void main(String args[]) {
        long num = 12345, sum = 0, remainder;
 
        while(num > 10) {
            sum = 0;
            System.out.format("sum digits of %d = " , num);
            while(num != 0) {
                remainder = num % 10;
                num = num / 10;
                sum += remainder;
            }
            System.out.format("%d\n", sum);
            if(sum > 10)
                num = sum;
            else
                break;
        }
        System.out.format("generic root = %d", sum);
    }
}




/*
run:
    
sum digits of 12345 = 15
sum digits of 15 = 6
generic root = 6
    
*/

 

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Answer 2

public class MyClass {
    public static void main(String args[]) {
        long num = 12345;
 
        long generic_root = 1 + ((num - 1) % 9);
        
        System.out.format("generic root = %d", generic_root);
    }
}




/*
run:
    
generic root = 6
    
*/

 

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