Question

How to calculate generic root of a number in JavaScript

Answer 1

// Generic Root of a number = sum of all the digits of the number until we get a single-digit
// 12345 : 1 + 2 + 3 + 4 + 5 = 15 : 1 + 5 = 6
// Generic Root of 12345 is 6

let num = 12345, sum, remainder;
 
while(num > 10) {
	sum = 0;
    let s = "sum digits of " + num + " = ";
    while(num) {
    	remainder = num % 10;
        num = Math.floor(num / 10);
        sum += remainder;
    }
    console.log(s + sum);
    if(sum > 10)
       num = sum;
    else
       break;
}
console.log("generic root = " + sum);
 
 
 
 
/*
run:
    
"sum digits of 12345 = 15"
"sum digits of 15 = 6"
"generic root = 6"
    
*/

 

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Answer 2

// Generic Root of a number = sum of all the digits of the number until we get a single-digit
// 12345 : 1 + 2 + 3 + 4 + 5 = 15 : 1 + 5 = 6
// Generic Root of 12345 is 6

const num = 12345;
 
const generic_root = 1 + ((num - 1) % 9);

console.log("generic root = " + generic_root);
 
 
 
 
/*
run:
    
"generic root = 6"
    
*/

 

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Answer 3

// Generic Root of a number = sum of all the digits of the number until we get a single-digit
// 12345 : 1 + 2 + 3 + 4 + 5 = 15 : 1 + 5 = 6
// Generic Root of 12345 is 6

const num = 12345;
let generic_root;
 
(generic_root = num % 9) ? num : 9;

console.log("generic root = " + generic_root);
 
 
 
 
/*
run:
    
"generic root = 6"
    
*/

 

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