Question

How to calculate generic root of a number in C#

Answer 1

using System;

class Program
{
    static void Main() {
        long num = 12345, sum = 0, remainder;
  
        while(num > 10) {
            sum = 0;
            Console.Write("sum digits of {0} = " , num);
            while(num != 0) {
                remainder = num % 10;
                num = num / 10;
                sum += remainder;
            }
            Console.Write("{0}\n", sum);
            if(sum > 10)
                num = sum;
            else
                break;
        }
        Console.Write("generic root = {0}", sum);
    }
}




/*
run:
     
sum digits of 12345 = 15
sum digits of 15 = 6
generic root = 6
     
*/

 

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Answer 2

using System;

class Program
{
    static void Main() {
        long num = 12345;
  
        long generic_root = 1 + ((num - 1) % 9);
        
        Console.Write("generic root = {0}", generic_root);
    }
}




/*
run:
     
generic root = 6
     
*/

 

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