Question

How to declare, initialize and print one-dimensional array of integers in C#

Answer 1

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            int[] arr = new int[] { 2, 234, 48, 17, 98, 918, 800, 12237, 100, 28 };

            for (int i = 0; i < arr.Length; i++)
                Console.WriteLine("arr[{0}] = {1}", i, arr[i]);
        }
    }
}

/*
run:
 
arr[0] = 2
arr[1] = 234
arr[2] = 48
arr[3] = 17
arr[4] = 98
arr[5] = 918
arr[6] = 800
arr[7] = 12237
arr[8] = 100
arr[9] = 28
  
*/

 

70+ SQL courses for beginners and professionals

Answer 2

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            int[] arr = new int[10] { 2, 234, 48, 17, 98, 918, 800, 12237, 100, 32 };

            for (int i = 0; i < arr.Length; i++)
                Console.WriteLine("arr[{0}] = {1}", i, arr[i]);
        }
    }
}

/*
run:
 
arr[0] = 2
arr[1] = 234
arr[2] = 48
arr[3] = 17
arr[4] = 98
arr[5] = 918
arr[6] = 800
arr[7] = 12237
arr[8] = 100
arr[9] = 32
  
*/

 

70+ SQL courses for beginners and professionals

Answer 3

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            int[] arr = new int[10];

            for (int i = 0; i < arr.Length; i++)
                arr[i] = i + 1;

            for (int i = 0; i < arr.Length; i++)
                Console.WriteLine("arr[{0}] = {1}", i, arr[i]);
        }
    }
}

/*
run:
 
arr[0] = 1
arr[1] = 2
arr[2] = 3
arr[3] = 4
arr[4] = 5
arr[5] = 6
arr[6] = 7
arr[7] = 8
arr[8] = 9
arr[9] = 10
  
*/

 

70+ SQL courses for beginners and professionals