Question

How to declare, initialize and print one-dimensional array of integers in C++

Answer 1

#include <iostream>

#define LEN 10
 
int main()
{
    int arr[LEN] = { 2, 234, 48, 17, 98, 918, 800, 12237, 100, 28 };
 
    for (int i = 0; i < LEN; i++) {
        std::cout << "arr[" << i << "] = " << arr[i] << "\n";
    }
}


 
/*
run: 
 
arr[0] = 2
arr[1] = 234
arr[2] = 48
arr[3] = 17
arr[4] = 98
arr[5] = 918
arr[6] = 800
arr[7] = 12237
arr[8] = 100
arr[9] = 28
 
*/

 

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Answer 2

#include <iostream>
 
int main()
{
    int arr[] = { 2, 234, 48, 17, 98, 918, 800, 12237, 100, 28 };
     
    int arr_size = sizeof(arr) / sizeof(arr[0]);
    
    for (int i = 0; i < arr_size; i++) {
        std::cout << "arr[" << i << "] = " << arr[i] << "\n";
    }
}
 
 
 
 
/*
run: 
 
arr[0] = 2
arr[1] = 234
arr[2] = 48
arr[3] = 17
arr[4] = 98
arr[5] = 918
arr[6] = 800
arr[7] = 12237
arr[8] = 100
arr[9] = 28
 
*/

 

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Answer 3

#include <iostream>

#define LEN 10
 
int main()
{
    int arr[LEN];
     
    for (int i = 0; i < LEN; i++) {
        arr[i] = i + 1;
    }
         
    for (int i = 0; i < LEN; i++) {
        std::cout << "arr[" << i << "] = " << arr[i] << "\n";
    }
     
    return 0;
}
 
 
 
/*
run: 
 
arr[0] = 1
arr[1] = 2
arr[2] = 3
arr[3] = 4
arr[4] = 5
arr[5] = 6
arr[6] = 7
arr[7] = 8
arr[8] = 9
arr[9] = 10
 
*/

 

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