Question

How to sort the digits of a number in descending order with Java

Answer 1

public class MyClass {
    public static void main(String args[]) {
        int n = 2314;
        int sortedNumber = 0;

        for (int i = 9; i >= 0; i--) {
            int tmp = n;
            while (tmp > 0) {
                int digit = tmp % 10;
                  if (digit == i) {
                    sortedNumber = sortedNumber * 10 + digit;
                }
                tmp /= 10;
            }
        }
        System.out.println(sortedNumber); 
    }
}
 
 
 
/*
run:
 
4321
 
*/

 

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