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How to sort the digits of a number in descending order with TypeScript

1 Answer

0 votes
function sortNumberDescending(num: number) {
	return Number(num.toString().split('').sort((a: any, b: any) => b - a).join(''));
}

let n: number = 38275;

n = sortNumberDescending(n)
  
console.log(n);
 
  
  
  
/*
run:
  
87532 
  
*/

 



answered Jan 19, 2024 by avibootz
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