Question

How to sort the digits of a number in descending order with Rust

Answer 1

fn sort_digits_descending (num: u32) -> u32 {
    let mut digits: Vec<char> = num.to_string().chars().collect();
    
    digits.sort();
    digits.reverse();
    
    // Convert the sorted vector to a string
    let sorted_str: String = digits.into_iter().collect();
    
    // Convert the string to a number
    sorted_str.parse::<u32>().unwrap()
}

fn main() {
    let number = 28371;
    
    let sorted_digits  = sort_digits_descending (number);
    
    println!("Sorted digits: {}", sorted_digits); 
}


    
/*
run:
 
Sorted digits: 87321
 
*/

 

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