Question

How to write if (n & 1) in Java

Answer 1

import java.io.*;  
   
public class MyClass {
    public static void main(String args[]) {
        int n = 179;
  
        System.out.println(Integer.toBinaryString(n));
        System.out.println(Integer.toBinaryString(n & 1));
 
        if ((n & 1) == 1) 
            System.out.println("Yes\n"); 
        else
            System.out.println("No\n"); 
             
             
        n = 178;
  
        System.out.println(Integer.toBinaryString(n));
        System.out.println(Integer.toBinaryString(n & 1));
 
        if ((n & 1) == 1) 
            System.out.println("Yes\n"); 
        else
            System.out.println("No\n"); 
    }
}
   
   
/*
run:
   
10110011
1
Yes

10110010
0
No
  
*/

 

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