How to find the missing number in an array containing numbers from 1 to n in O(1) time complexity with Java

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// The essence of O(1) space complexity is that the algorithm uses a fixed amount of memory,
// regardless of input size. Time complexity here is O(n) because we must scan the array.

public class MissingNumberFinder {

    public static int findMissingNumber(int[] arr) {
        int size = arr.length;
        // formula for the sum of the first (size+1) natural numbers
        long expectedSum = (long)(size + 1) * (size + 2) / 2;
        long actualSum = 0;

        for (int i = 0; i < size; i++) {
            actualSum += arr[i];
        }

        return (int)(expectedSum - actualSum);
    }

    public static void main(String[] args) {
        int[] arr = {1, 2, 4, 5, 6};
        int missing = findMissingNumber(arr);

        System.out.println("Missing number: " + missing);
    }
}


/*
run:

Missing number: 3

*/

 



answered Dec 10, 2025 by avibootz

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