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How to generate an n x n matrix filled with elements from 1 to N^2 in spiral order in Java

1 Answer

0 votes
import java.util.Arrays;

public class SpiralMatrixGenerator {

    public static int[][] generateSpiralMatrix(int n) {
        int[][] matrix = new int[n][n];
        int top = 0, bottom = n - 1;
        int left = 0, right = n - 1;
        int num = 1;

        while (top <= bottom && left <= right) {
            // Fill top row
            for (int i = left; i <= right; ++i) {
                matrix[top][i] = num++;
            }
            top++;

            // Fill right column
            for (int i = top; i <= bottom; ++i) {
                matrix[i][right] = num++;
            }
            right--;

            // Fill bottom row
            if (top <= bottom) {
                for (int i = right; i >= left; --i) {
                    matrix[bottom][i] = num++;
                }
                bottom--;
            }

            // Fill left column
            if (left <= right) {
                for (int i = bottom; i >= top; --i) {
                    matrix[i][left] = num++;
                }
                left++;
            }
        }

        return matrix;
    }

    public static void main(String[] args) {
        int n = 3; // size of the matrix
        int[][] spiralMatrix = generateSpiralMatrix(n);

        // Print the matrix
        for (int[] row : spiralMatrix) {
            for (int val : row) {
                System.out.print(val + "\t");
            }
            System.out.println();
        }
    }
}


/*
run:

1	2	3	
8	9	4	
7	6	5

*/


 



answered Jun 24, 2025 by avibootz
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