How to calculates the frequency of odd and even numbers in the given matrix with Swift

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/*
    Function: countOddEven
    Purpose:  Counts how many odd and even numbers exist in the matrix.
    Parameters:
        - matrix: the 2D array
        - rows:   number of rows in the matrix   (computed inside the function)
        - cols:   number of columns in the matrix (computed inside the function)
        - odd:    variable to store odd count
        - even:   variable to store even count
*/
func countOddEven(_ matrix: [[Int]]) -> (odd: Int, even: Int) {

    // Automatically compute matrix dimensions inside the function
    let rows: Int = matrix.count
    let cols: Int = matrix[0].count

    var odd: Int = 0
    var even: Int = 0

    for i in 0..<rows {
        for j in 0..<cols {

            // Check if the number is even or odd
            if matrix[i][j] % 2 == 0 {
                even += 1
            } else {
                odd += 1
            }
        }
    }

    return (odd, even)
}

func main() {

    let matrix: [[Int]] = [
        [1, 0, 2, 5],
        [3, 5, 6, 9],
        [7, 4, 1, 8]
    ]

    // Call the function (rows and cols are now computed inside)
    let result = countOddEven(matrix)
    let oddCount = result.odd
    let evenCount = result.even

    // Display the result
    print("The frequency of odd numbers = \(oddCount)")
    print("The frequency of even numbers = \(evenCount)")
}

main()


/*
run:

The frequency of odd numbers = 7
The frequency of even numbers = 5

*/

 



answered 3 days ago by avibootz

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