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How to calculates the frequency of odd and even numbers in the given matrix with Go

1 Answer

0 votes
package main

import (
    "fmt"
)

/*
    Function: countOddEven
    Purpose:  Counts how many odd and even numbers exist in the matrix.
    Parameters:
        - matrix: the 2D slice
        - rows:   number of rows in the matrix   (computed inside the function)
        - cols:   number of columns in the matrix (computed inside the function)
        - odd:    variable to store odd count
        - even:   variable to store even count
*/
func countOddEven(matrix [][]int) (int, int) {

    // Automatically compute matrix dimensions inside the function
    rows := len(matrix)
    cols := len(matrix[0])

    odd := 0
    even := 0

    for i := 0; i < rows; i++ {
        for j := 0; j < cols; j++ {

            // Check if the number is even or odd
            if matrix[i][j]%2 == 0 {
                even++
            } else {
                odd++
            }
        }
    }

    return odd, even
}

func main() {

    matrix := [][]int{
        {1, 0, 2, 5},
        {3, 5, 6, 9},
        {7, 4, 1, 8},
    }

    // Call the function (rows and cols are now computed inside)
    oddCount, evenCount := countOddEven(matrix)

    // Display the result
    fmt.Println("The frequency of odd numbers =", oddCount)
    fmt.Println("The frequency of even numbers =", evenCount)
}


/*
run:

The frequency of odd numbers = 7
The frequency of even numbers = 5

*/

 



answered Jul 2 by avibootz

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