How to determine whether an n‑bit binary number is divisible by 5 in Swift

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import Foundation

// function to compute whether a binary number is divisible by 5
// it processes the bits left to right and keeps track of the remainder modulo 5
// for each bit b:
//     remainder = (remainder * 2 + b) % 5
func isDivisibleByFive(_ bin: String) -> Bool {

    // remainder modulo 5 while scanning bits
    var remainder: Int = 0

    // scan each bit of the binary number
    for bit in bin {

        // convert '0' or '1' to integer 0 or 1
        let b: Int = Int(bit.asciiValue! - Character("0").asciiValue!)

        // update remainder using modulo arithmetic
        remainder = (remainder * 2 + b) % 5
    }

    // divisible if final remainder is zero
    return remainder == 0
}


// read an n-bit binary number as a string
let bin: String = "01000110"   // 70

let divisible: Bool = isDivisibleByFive(bin)

print("Binary number: \(bin)")
print("Divisible by 5: \(divisible ? "yes" : "no")")

/*
  Example walk-through for bin = 01000110:

  Start: remainder = 0

  bit = 0 → remainder = (0*2 + 0) % 5 = 0
  bit = 1 → remainder = (0*2 + 1) % 5 = 1
  bit = 0 → remainder = (1*2 + 0) % 5 = 2
  bit = 0 → remainder = (2*2 + 0) % 5 = 4
  bit = 0 → remainder = (4*2 + 0) % 5 = 3
  bit = 1 → remainder = (3*2 + 1) % 5 = 2
  bit = 1 → remainder = (2*2 + 1) % 5 = 0
  bit = 0 → remainder = (0*2 + 0) % 5 = 0

  Final remainder = 0 → divisible by 5
*/


/*
run:

Binary number: 01000110
Divisible by 5: yes

*/

 



answered Jun 28 by avibootz

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