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How to determine whether an n‑bit binary number is divisible by 5 in Go

1 Answer

0 votes
package main

import (
    "fmt"
)

// function to compute whether a binary number is divisible by 5
// it processes the bits left to right and keeps track of the remainder modulo 5
// for each bit b:
//     remainder = (remainder * 2 + b) % 5
func isDivisibleByFive(bin string) bool {

    // remainder modulo 5 while scanning bits
    remainder := 0

    // scan each bit of the binary number
    for _, bit := range bin {

        // convert '0' or '1' to integer 0 or 1
        b := int(bit - '0')

        // update remainder using modulo arithmetic
        remainder = (remainder*2 + b) % 5
    }

    // divisible if final remainder is zero
    return remainder == 0
}

func main() {

    // read an n-bit binary number as a string
    bin := "01000110" // 70

    divisible := isDivisibleByFive(bin)

    fmt.Println("Binary number:", bin)
    fmt.Println("Divisible by 5:", func() string {
        if divisible {
            return "yes"
        }
        return "no"
    }())

    /*
      Example walk-through for bin = 01000110:

      Start: remainder = 0

      bit = 0 → remainder = (0*2 + 0) % 5 = 0
      bit = 1 → remainder = (0*2 + 1) % 5 = 1
      bit = 0 → remainder = (1*2 + 0) % 5 = 2
      bit = 0 → remainder = (2*2 + 0) % 5 = 4
      bit = 0 → remainder = (4*2 + 0) % 5 = 3
      bit = 1 → remainder = (3*2 + 1) % 5 = 2
      bit = 1 → remainder = (2*2 + 1) % 5 = 0
      bit = 0 → remainder = (0*2 + 0) % 5 = 0

      Final remainder = 0 → divisible by 5
    */
}


/*
run:

Binary number: 01000110
Divisible by 5: yes

*/

 



answered Jun 28 by avibootz

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