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How to product of array except self (arr[i] is equal to the product of all the elements except arr[i]) in Python

1 Answer

0 votes
"""
    Computes product of array except self.
    nums   = input list
    returns a new list containing the result
"""
def product_except_self(nums):
    size = len(nums)
    answer = [0] * size   # allocate output list

    prefix = 1

    # ---- Prefix products ----
    # answer[i] gets product of all elements before i
    for i in range(size):
        answer[i] = prefix        # store prefix product
        prefix *= nums[i]         # update prefix
        # Example for nums = [5,2,3,4]:
        # prefix values: 1, 5, 10, 30

    # ---- Suffix products ----
    # Multiply each answer[i] by product of all elements after i
    suffix = 1
    for i in range(size - 1, -1, -1):
        answer[i] *= suffix       # combine prefix * suffix
        suffix *= nums[i]         # update suffix
        # suffix values: 1, 4, 12, 24, 120
        # final answer: 24, 60, 40, 30
        # 24 (24*1) 60 (12*5) 40 (10*4) 30 (30*1)

    return answer


def main():
    arr = [5, 2, 3, 4]

    result = product_except_self(arr)

    print("Result:", *result)


if __name__ == "__main__":
    main()



"""
run:

Result: 24 60 40 30

"""

 



answered Jan 3 by avibootz

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