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How to product of array except self (arr[i] is equal to the product of all the elements except arr[i]) in Rust

1 Answer

0 votes
// Computes product of array except self.
// nums   = input vector
// returns a new vector containing the result
fn product_except_self(nums: &Vec<i32>) -> Vec<i32> {
    let size = nums.len();
    let mut answer = vec![1; size];

    // ---- Prefix products ----
    // answer[i] gets the product of all elements before i
    let mut prefix = 1;
    for i in 0..size {
        answer[i] = prefix;        // store prefix product
        prefix *= nums[i];         // update prefix
        // Example for nums = [5,2,3,4]:
        // prefix values: 1, 5, 10, 30
    }

    // ---- Suffix products ----
    // Multiply each answer[i] by product of all elements after i
    let mut suffix = 1;
    for i in (0..size).rev() {
        answer[i] *= suffix;       // combine prefix * suffix
        suffix *= nums[i];         // update suffix
        // suffix values: 1, 4, 12, 24, 120
        // final answer: 24, 60, 40, 30
        // 24 (24*1) 60 (12*5) 40 (10*4) 30 (30*1)
    }

    answer
}

fn main() {
    let arr = vec![5, 2, 3, 4];

    let result = product_except_self(&arr);

    print!("Result: ");
    for x in result {
        print!("{} ", x);
    }
}



/*
run:

Result: 24 60 40 30 

*/

 



answered Jan 3 by avibootz

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