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How to product of array except self (arr[i] is equal to the product of all the elements except arr[i]) in C#

1 Answer

0 votes
using System;

class Program
{
    /*
        Computes product of array except self.
        nums   = input array
        size   = number of elements
        returns a new array containing the result
    */
    static int[] ProductExceptSelf(int[] nums, int size) {
        int[] answer = new int[size];   // allocate output array
        int prefix = 1;

        // ---- Prefix products ----
        // answer[i] gets product of all elements before i
        for (int i = 0; i < size; i++) {
            answer[i] = prefix;     // store prefix product
            prefix *= nums[i];      // update prefix
            // Example for nums = {5,2,3,4}:
            // prefix values: 1, 5, 10, 30
        }

        // ---- Suffix products ----
        // Multiply each answer[i] by product of all elements after i
        int suffix = 1;
        for (int i = size - 1; i >= 0; i--) {
            answer[i] *= suffix;    // combine prefix * suffix
            suffix *= nums[i];      // update suffix
            // suffix values: 1, 4, 12, 24, 120
            // final answer: 24, 60, 40, 30
            // 24 (24*1) 60 (12*5) 40 (10*4) 30 (30*1)
        }

        return answer;
    }

    static void Main()
    {
        int[] arr = { 5, 2, 3, 4 };
        int size = arr.Length;

        int[] result = ProductExceptSelf(arr, size);

        Console.Write("Result: ");
        for (int i = 0; i < size; i++) {
            Console.Write(result[i] + " ");
        }
    }
}


/*
run:

Result: 24 60 40 30

*/


 



answered Jan 3 by avibootz
edited Jan 3 by avibootz

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