How to product of array except self (arr[i] is equal to the product of all the elements except arr[i]) in Java

1 Answer

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public class ProductExceptSelf {

    // Computes product of array except self.
    // nums   = input array
    // size   = number of elements
    // returns a new array containing the result
    static int[] productExceptSelf(int[] nums, int size) {
        int[] answer = new int[size];   // allocate output array
        int prefix = 1;

        // ---- Prefix products ----
        // answer[i] gets the product of all elements before i
        for (int i = 0; i < size; i++) {
            answer[i] = prefix;      // store prefix product
            prefix *= nums[i];       // update prefix
            // Example for nums = {5,2,3,4}:
            // prefix values: 1, 5, 10, 30
        }

        // ---- Suffix products ----
        // Multiply each answer[i] by product of all elements after i
        int suffix = 1;
        for (int i = size - 1; i >= 0; i--) {
            answer[i] *= suffix;     // combine prefix * suffix
            suffix *= nums[i];       // update suffix
            // suffix values: 1, 4, 12, 24, 120
            // final answer: 24, 60, 40, 30
            // 24 (24*1) 60 (12*5) 40 (10*4) 30 (30*1)
        }

        return answer;
    }

    public static void main(String[] args) {
        int[] arr = {5, 2, 3, 4};
        int size = arr.length;

        int[] result = productExceptSelf(arr, size);

        System.out.print("Result: ");
        for (int x : result) {
            System.out.print(x + " ");
        }
    }
}


/*
run:

Result: 24 60 40 30 

*/

 



answered Jan 2 by avibootz
edited Jan 3 by avibootz

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