Welcome to collectivesolver - Programming & Software Q&A with code examples. A website with trusted programming answers. All programs are tested and work.

Contact: aviboots(AT)netvision.net.il

Buy a domain name - Register cheap domain names from $0.99 - Namecheap

Scalable Hosting That Grows With You

Secure & Reliable Web Hosting, Free Domain, Free SSL, 1-Click WordPress Install, Expert 24/7 Support

Semrush - keyword research tool

Boost your online presence with premium web hosting and servers

Disclosure: My content contains affiliate links.

39,988 questions

51,933 answers

573 users

How to clear bits in the given range in Java

1 Answer

0 votes
public class ClearBitsRange {

    // Print bits of a 32-bit integer
    static void printBits(int x, String label) {
        String bits = String.format("%32s", Integer.toBinaryString(x))
                           .replace(' ', '0');
        System.out.println(label + ": " + bits);
    }

    // Clear bits in range [l, r] inclusive (0 = least significant bit)
    static int clearBits(int x, int l, int r) {
        if (l < 0 || r > 31 || l > r) {
            throw new IllegalArgumentException("Invalid bit range");
        }

        // maskLeft:
        // Create a mask with 1s above bit r and 0s from bit r down to 0.
        // Example: r = 5 → maskLeft = 11111111 11111111 11111111 11000000
        int maskLeft = ~0 << (r + 1);
        printBits(maskLeft, "maskLeft ");

        // maskRight:
        // Create a mask with 1s below bit l and 0s from bit l upward.
        // Example: l = 3 → maskRight = 00000000 00000000 00000000 00000111
        int maskRight = (1 << l) - 1;
        printBits(maskRight, "maskRight");

        // Combine both masks:
        // maskLeft keeps bits above r.
        // maskRight keeps bits below l.
        // The range [l, r] becomes 0s.
        int mask = maskLeft | maskRight;
        printBits(mask, "mask     ");

        return x & mask;
    }

    public static void main(String[] args) {

        int value = 0b11111100111111001111110011111100;

        int l = 3;   // start bit
        int r = 10;  // end bit

        int result = clearBits(value, l, r);

        printBits(value,  "Before   ");
        printBits(result, "After    ");
    }
}



/*
run:

maskLeft : 11111111111111111111100000000000
maskRight: 00000000000000000000000000000111
mask     : 11111111111111111111100000000111
Before   : 11111100111111001111110011111100
After    : 11111100111111001111100000000100

*/

 



answered Dec 29, 2025 by avibootz
...