How to clear bits in the given range in Scala

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object ClearBitsRange {

  // Print bits of a 32-bit integer
  def printBits(x: Int, label: String): Unit = {
    // Convert to binary and pad to 32 bits
    val bits = String.format("%32s", Integer.toBinaryString(x & 0xFFFFFFFF))
      .replace(' ', '0')
    println(s"$label: $bits")
  }

  // Clear bits in range [l, r] inclusive (0 = least significant bit)
  def clearBits(x: Int, l: Int, r: Int): Int = {
    if (l < 0 || r > 31 || l > r)
      throw new IllegalArgumentException("Invalid bit range")

    // maskLeft:
    // Create a mask with 1s above bit r and 0s from bit r down to 0.
    // Example: r = 5 → maskLeft = 11111111 11111111 11111111 11000000
    val maskLeft = (~0 << (r + 1)) & 0xFFFFFFFF
    printBits(maskLeft, "maskLeft ")

    // maskRight:
    // Create a mask with 1s below bit l and 0s from bit l upward.
    // Example: l = 3 → maskRight = 00000000 00000000 00000000 00000111
    val maskRight = ((1 << l) - 1) & 0xFFFFFFFF
    printBits(maskRight, "maskRight")

    // Combine both masks:
    // maskLeft keeps bits above r.
    // maskRight keeps bits below l.
    // The range [l, r] becomes 0s.
    val mask = (maskLeft | maskRight) & 0xFFFFFFFF
    printBits(mask, "mask     ")

    x & mask
  }

  def main(args: Array[String]): Unit = {
    val value = 0b11111100111111001111110011111100

    val l = 3   // start bit
    val r = 10  // end bit

    val result = clearBits(value, l, r)

    printBits(value,  "Before   ")
    printBits(result, "After    ")
  }
}




/*
run:

maskLeft : 11111111111111111111100000000000
maskRight: 00000000000000000000000000000111
mask     : 11111111111111111111100000000111
Before   : 11111100111111001111110011111100
After    : 11111100111111001111100000000100

*/

 



answered Dec 30, 2025 by avibootz
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