Question

How to get the 4 least significant bits in a byte with Kotlin

Answer 1

fun main() {
    val value: Byte = 0xD6.toByte()
    val lower4: Int = value.toInt() and 0x0F

    println("value  (dec): ${value.toInt() and 0xFF}")  // show as unsigned 214
    println("lower4 (dec): $lower4")

    val valueBin  = (value.toInt() and 0xFF).toString(2).padStart(8, '0')
    val lower4Bin = lower4.toString(2).padStart(4, '0')

    println("value  (bin):  $valueBin")
    println("lower4 (bin):  $lower4Bin")
}



/*
run:

value  (dec): 214
lower4 (dec): 6
value  (bin):  11010110
lower4 (bin):  0110

*/

 

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