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How to get the 4 least significant bits in a byte with Scala

1 Answer

0 votes
object Lower4Bits extends App {
  val value: Byte = 0xD6.toByte          // 1101 0110
  val lower4: Int = value & 0x0F         // keep only 4 LSBs

  println("value  (dec): " + (value & 0xFF))   // show as unsigned 214
  println("lower4 (dec): " + lower4)

  val valueBin  = String.format("%8s", Integer.toBinaryString(value & 0xFF)).replace(' ', '0')
  val lower4Bin = String.format("%4s", Integer.toBinaryString(lower4)).replace(' ', '0')

  println("value  (bin):  " + valueBin)
  println("lower4 (bin):  " + lower4Bin)
}




/*
run:

value  (dec): 214
lower4 (dec): 6
value  (bin):  11010110
lower4 (bin):  0110

*/

 



answered Dec 28, 2025 by avibootz
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