How to find the second biggest number in a set of random numbers in Java

1 Answer

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import java.util.Random;

public class SecondMaxFinder {

    public static int findSecondMax(int total, int rndmax) {
        Random rand = new Random();
        int max, beforeMax, n;

        n = rand.nextInt(rndmax) + 1;
        System.out.println(n);
        max = beforeMax = n;

        for (int i = 1; i < total; i++) {
            n = rand.nextInt(rndmax) + 1;
            System.out.println(n);
            if (n > max) {
                beforeMax = max;
                max = n;
            } else if (n > beforeMax) {
                beforeMax = n;
            }
        }

        return beforeMax;
    }

    public static void main(String[] args) {
        int secondMax = findSecondMax(10, 100);

        System.out.println("The second biggest number is: " + secondMax);
    }
}



/*
run:

91
93
22
34
18
64
42
90
19
81
The second biggest number is: 91

*/

 



answered Oct 4, 2025 by avibootz
edited Oct 4, 2025 by avibootz

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