Question

How to find the second biggest number in a set of random numbers in Scala

Answer 1

import scala.util.Random

object SecondMaxFinder {
  def findSecondMax(total: Int, rndmax: Int): Option[Int] = {
    val rng = new Random()
    val numbers = List.fill(total) {
      val n = rng.between(1, rndmax + 1)
      println(n)
      n
    }

    val uniqueSorted = numbers.distinct.sorted(Ordering[Int].reverse)
    uniqueSorted.drop(1).headOption
  }

  def main(args: Array[String]): Unit = {
    val secondMax = findSecondMax(10, 100)
    secondMax match {
      case Some(value) => println(s"The second biggest number is: $value")
      case None => println("Not enough unique numbers to determine a second maximum.")
    }
  }
}



/*
run:

6
30
95
34
84
100
1
1
18
19
The second biggest number is: 95

*/

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