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How to find repeated patterns of numbers in the rows of a matrix with Kotlin

1 Answer

0 votes
fun findRepeatingPatterns(matrix: List<List<Int>>, patternSize: Int) {
    val patternMap = mutableMapOf<String, MutableSet<Int>>()

    matrix.forEachIndexed { rowIndex, row ->
        for (col in 0..row.size - patternSize) {
            val pattern = row.subList(col, col + patternSize).joinToString("-")

            patternMap.getOrPut(pattern) { mutableSetOf() }.add(rowIndex)
        }
    }

    println("Repeated Patterns Found:")
    patternMap.forEach { (pattern, rows) ->
        if (rows.size > 1) {
            println("$pattern appears ${rows.size} times in rows: ${rows.joinToString(" ")}")
        }
    }
}

fun main() {
    val matrix = listOf(
        listOf(1, 2, 3, 8, 9, 7, 4, 9, 6),
        listOf(1, 3, 2, 7, 8, 9, 4, 5, 6),
        listOf(1, 2, 3, 8, 6, 1, 4, 9, 8),
        listOf(1, 2, 3, 0, 8, 8, 4, 5, 9),
        listOf(1, 2, 3, 4, 5, 6, 7, 8, 9),
        listOf(1, 2, 3, 7, 0, 9, 4, 5, 7),
        listOf(1, 3, 2, 4, 5, 6, 7, 8, 9)
    )

    val patternSize = 3 // Looking for sequences of 3 numbers
    
    findRepeatingPatterns(matrix, patternSize)
}


 
/*
run:
 
Repeated Patterns Found:
1-2-3 appears 5 times in rows: 0 2 3 4 5
2-3-8 appears 2 times in rows: 0 2
1-3-2 appears 2 times in rows: 1 6
7-8-9 appears 3 times in rows: 1 4 6
9-4-5 appears 2 times in rows: 1 5
4-5-6 appears 3 times in rows: 1 4 6
5-6-7 appears 2 times in rows: 4 6
6-7-8 appears 2 times in rows: 4 6
 
*/

 



answered May 25, 2025 by avibootz
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