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How to write an algorithm that add the odd digits of one number to the end of a second number in C

2 Answers

0 votes
#include <stdio.h>

int add_odd_digits(int n, int second_n);
  
int main(void)
{
    int n = 12734, second_n = 100;
 
    printf("%d\n", add_odd_digits(n, second_n));
         
    return 0;
}
  
int add_odd_digits(int n, int second_n)
{
    int multiply = 1, odd = 0;
     
    while (n != 0)
    {
        if (n % 2 != 0)
        {
            odd += (n % 10) * multiply;
            multiply *= 10;
        }
        n = n / 10;
    }
 
    return second_n * multiply + odd;
}
  
/*
  
run:
  
100173

*/


answered Nov 5, 2014 by avibootz
edited Feb 22, 2015 by avibootz
0 votes
#include <stdio.h> 
 
int main(void)
{
    int n = 12734, second_n = 100, multiply = 1, odd = 0;
      
    while (n != 0)
    {
        if (n % 2 != 0)
        {
            odd += (n % 10) * multiply;
            multiply *= 10;
        }
        n = n / 10;
    }
  
    printf("%d\n", second_n * multiply + odd);
    
    return 0;

}
   
/*
   
run:
   
100173
 
*/

 


answered Feb 22, 2015 by avibootz
...