How to write an algorithm that adds the odd digits of one number to the end of a second number in Swift

1 Answer

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import Foundation

func addOddDigits(_ n: Int, _ second_n: Int) -> Int {
    var multiply = 1
    var odd = 0
    var number = n
 
    while number != 0 {
        if number % 2 != 0 {
            odd += (number % 10) * multiply
            multiply *= 10
        }
         
        number /= 10
    }
 
    return second_n * multiply + odd
}
 
let n = 12734
let second_n = 100
 
print(addOddDigits(n, second_n))
 
 
 
/*
run:
 
100173
 
*/

 



answered Nov 6, 2024 by avibootz
edited Nov 6, 2024 by avibootz
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