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How to use TypedArray.fill() to fill all typed array elements from a start index to end index with value in JavaScript

6 Answers

0 votes
// typedarray.fill(value[, start = 0[, end = this.length]])
 
const arr = new Uint8Array([1, 2, 3]).fill(5); 

for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
     
     
 
 
/*
run:
 
5
5
5
 
*/

 



answered Aug 12, 2016 by avibootz
edited Nov 20, 2022 by avibootz
0 votes
// typedarray.fill(value[, start = 0[, end = this.length]])
 
const arr = new Uint8Array([1, 2, 3, 4, 9, 10]).fill(5, 2); 

for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
 
 
 
 
/*
run:
 
1
2
5
5
5
5
 
*/

 



answered Aug 13, 2016 by avibootz
edited Nov 20, 2022 by avibootz
0 votes
// typedarray.fill(value[, start = 0[, end = this.length]])
 
const arr = new Uint8Array([1, 2, 3, 4, 9, 10]).fill(5, 1, 3); 

for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
 
 
 
 
/*
run:
 
1
5
5
4
9
10
 
*/

 



answered Aug 13, 2016 by avibootz
edited Nov 20, 2022 by avibootz
0 votes
// typedarray.fill(value[, start = 0[, end = this.length]])
 
const arr = new Uint8Array([1, 2, 3, 4, 9, 10]).fill(5, 1, 1); 

for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
 
 
 
 
/*
run:
 
1
2
3
4
9
10
 
*/

 



answered Aug 13, 2016 by avibootz
edited Nov 20, 2022 by avibootz
0 votes
// typedarray.fill(value[, start = 0[, end = this.length]])

// If start is negative, it is treated as length + start
// If end is negative, it is treated as length + end.
 
const arr = new Uint8Array([1, 2, 3, 4]).fill(5, -3, -1); 

for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
 
 
 
 
/*
run:
 
1
5
5
4
 
*/

 



answered Aug 13, 2016 by avibootz
edited Nov 20, 2022 by avibootz
0 votes
// typedarray.fill(value[, start = 0[, end = this.length]])

// If start is negative, it is treated as length + start
// If end is negative, it is treated as length + end.
 
const arr = new Uint8Array([1, 2, 3, 4]).fill(5, -3, 2); 

for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
 
 
 
 
/*
run:
 
1
5
3
4
 
*/

 



answered Aug 13, 2016 by avibootz
edited Nov 20, 2022 by avibootz
...