Question

How to use TypedArray.fill() to fill all typed array elements from a start index to end index with value in TypeScript

Answer 1

// typedarray.fill(value[, start = 0[, end = this.length]])
  
const arr = new Uint8Array([1, 2, 3]).fill(5); 
 
for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
      
      
  
  
/*
run:
  
5
5
5
  
*/

 

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Answer 2

// typedarray.fill(value[, start = 0[, end = this.length]])
  
const arr = new Uint8Array([1, 2, 3, 4, 9, 10, 12]).fill(5, 2); 
 
for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
  
  
  
  
/*
run:
  
1
2
5
5
5
5
5
  
*/

 

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Answer 3

// typedarray.fill(value[, start = 0[, end = this.length]])
  
const arr = new Uint8Array([1, 2, 3, 4, 9, 10, 11]).fill(5, 1, 3); 
 
for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
  
  
  
  
/*
run:
  
1
5
5
4
9
10
11
  
*/

 

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Answer 4

// typedarray.fill(value[, start = 0[, end = this.length]])
  
const arr = new Uint8Array([1, 2, 3, 4, 9, 10, 14]).fill(5, 1, 1); 
 
for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
  
  
  
  
/*
run:
  
1
2
3
4
9
10
14
  
*/

 

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Answer 5

// typedarray.fill(value[, start = 0[, end = this.length]])
 
// If start is negative, it is treated as length + start
// If end is negative, it is treated as length + end.
  
const arr = new Uint8Array([1, 2, 3, 4, 6]).fill(5, -3, -1); 
 
for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
  
  
  
  
/*
run:
  
1
2
5
5
6
  
*/

 

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Answer 6

// typedarray.fill(value[, start = 0[, end = this.length]])
 
// If start is negative, it is treated as length + start
// If end is negative, it is treated as length + end.
  
const arr = new Uint8Array([1, 2, 3, 4,]).fill(5, -3, 2); 
 
for (let i = 0; i < arr.length; i++)
    console.log(arr[i]);
  
  
  
  
/*
run:
  
1
5
3
4
  
*/

 

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