Question

How to get the first x leftmost digits of an integer number in Kotlin

Answer 1

fun xLeftmostDigit(n: Int, x: Int): Int {
    var num = n
    val divisor = Math.pow(10.0, x.toDouble()).toInt()
    while (num > divisor) {
        num /= 10
    }
    return num
}

fun main() {
    for (i in 1..5) {
        val n = (1..100000).random()
        val x = (1..5).random()
        println("$x leftmost digit of $n is ${xLeftmostDigit(n, x)}")
    }
}


 
/*
run:

3 leftmost digit of 69924 is 699
3 leftmost digit of 39873 is 398
1 leftmost digit of 12978 is 1
1 leftmost digit of 39613 is 3
2 leftmost digit of 98458 is 98
 
*/

 

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